4^x+1=1/8^-2x

Solution for 4^x+1=1/8^-2x equation:

4^x+1=1/8^-2x

We move all terms to the left:

4^x+1-(1/8^-2x)=0


Domain of the equation: 8^-2x)!=0

x∈R


We get rid of parentheses

4^x+2x+1-1/8^=0

We multiply all the terms by the denominator


4^x*8^+2x*8^-1+1*8^=0

We add all the numbers together, and all the variables

4^x*8^+2x*8^=0

Wy multiply elements

32x^2+16x^2=0

We add all the numbers together, and all the variables

48x^2=0

a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{96}=0$